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hey did any body watch the dirt rider adventure on oln last night. there were some pretty sick shees, i also saw a guy that had his front shocks turned up side where the shaft that sticks out of the shock is facing down what does this do? they showed drag racing to if you didnt know what time it comes on its on oln on thursday at 7:30 and 10:30. i think thats central time what ever time texas is in. well ill talk to you guys latre.

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MotulMonsta Posted on Mar 12 2004, 10:18 AM

  turning the shock's upside down reduces unsprung weight

NO IT DOES NOT, the only way to reduce "un spring" weight would be to remove heavy parts and replace them with lighter parts, or leave them off all together.

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Unsprung weight is the wight that isn't carried by the machine's suspension. Too much unsprung wight will cause you to become bouncy. unsprung weight can be considered everything below the springs of the shock. With upsidedown shocks, the oil is below the centerline of the shock and add a bit of unsprung weight. Not much, but it's there. So when you turn the shocks rightside up you put that weight above the centerline of the springs and decrease unsprung weight. Take a shock and find the ballance point of it. then find the center of the spring. everything below the center adds to unsprung weight.

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Unsprung weight is described as ANYTHING being controlled by the spring / shock combination. The shock does not know that it is upsidedown, and you have not eliminated any weight by installing it upsidedown. Thus no change in unsprung weight.

Take a shock and find the ballance point of it

Please explain to us how this is done and what exactly this is, or are you just pulling this stuff out of your ass? I do suspension design / engineering for a living and have never heard of a shocks "ballance point"

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Damn I'm being attacked on all sides here :blink: ..you design suspension parts then you should know what i'm talkin about. Why did dirtbikes go from upside down to rightside up forks?? Why do all high performance shocks run rightside up as well? To find the ballance point of the shock, set it on a stock or somthing and get it to ballance. But the ballance point doesn't really matter, it's where the weight of the shock is located. You want as much weight as possible above the spring. When I first leaned of this too, it took me a while to understand what the f*ck the dude was talking about. Maybe I'm not explaining myself well enough here. Maybe I'm just hard headed. I could be wrong. I'm no paid professional or nothing on engeneering and shock designs.

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Not trying to attack you, just trying to prevent members from being miss-led by your wrong information. Some of the information you post is just flat wrong thats all.

you design suspension parts then you should know what i'm talkin about.
But the ballance point doesn't really matter,

That was my point, "ballance points" of shocks / springs is not done in the industry, it is of no value, and is frankly a bogus term.

 

If you have an opinion or idea about something that is fine, you are entitled to that, just don't post BS as if it's fact.

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I agree with MotulMonsta, he's talking about unsprung weight vs. sprung weight. O.K look at a shock, it has one end that holds all the oil, has the larger spring in a dual/triple rate system, the other end has the smaller spring and only has the shaft attached to the eyelet. Now take the shock and try to balance it horizontally in your hand, you'll notice that you have to have your hand closer to the part that holds the oil to keep it from tilting and falling on the floor. Now you see this side is the heavier side of the shock.

 

Now, when you put it on your shee like normal, the lower part is the heavier side which means the lighter is attached to the frame. When you hit a bump the wieght of the rider, upper frame, and the upper eyelet weight, shafts weight all create a force (F=ma) into the lower part of the shock through the springs.

 

Now flip that shock upside down, you hit a bump and the weight of the rider and frame hasn't changed but now you have that heavier end of the shock pushing downwards into the smaller end, so since F=ma (mass is now greater) the downward force is now greater than the other setup.

 

So now that you can see how the top of a shock is sprung and the bottom is unsprung. By flipping the shock upside down you have more sprung weight (not sure if its really significant) but that's the physics of it.

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OK I give, MotulMonsta I apoligize, you are correct, you reduce the unsprung weight of the suspension assembly by only the weight of the oil which is minimal at best. What you guys fail to realizie is that the individual suspensions corner weight vs the minimal change in unsprung weight is cancelled by the suspension frequency at that corner, which is based on the wheel rate. The wheel rate is derived from the spring rate and tha calculated motion ratio. Still with me? Bottom line is that if you were to "flip" your front shocks, with out some on-board data logging equipment to show you changes in frequency and oscillation you will not feel / tell a difference. Why do none of the "Pro's" or aftermarket shock companies build / mount shocks this way? Because the difference in unsprung weight, and spring rate needed to control the suspensions movement is neglidgeable.

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